+ ret = read_tree(buffer, size, stage, NULL);
+ free(buffer);
+ return ret;
+}
+
+static int path_matches(struct cache_entry *a, struct cache_entry *b)
+{
+ int len = ce_namelen(a);
+ return ce_namelen(b) == len &&
+ !memcmp(a->name, b->name, len);
+}
+
+static int same(struct cache_entry *a, struct cache_entry *b)
+{
+ return a->ce_mode == b->ce_mode &&
+ !memcmp(a->sha1, b->sha1, 20);
+}
+
+
+/*
+ * This removes all trivial merges that don't change the tree
+ * and collapses them to state 0.
+ */
+static struct cache_entry *merge_entries(struct cache_entry *a,
+ struct cache_entry *b,
+ struct cache_entry *c)
+{
+ /*
+ * Ok, all three entries describe the same
+ * filename, but maybe the contents or file
+ * mode have changed?
+ *
+ * The trivial cases end up being the ones where two
+ * out of three files are the same:
+ * - both destinations the same, trivially take either
+ * - one of the destination versions hasn't changed,
+ * take the other.
+ *
+ * The "all entries exactly the same" case falls out as
+ * a special case of any of the "two same" cases.
+ *
+ * Here "a" is "original", and "b" and "c" are the two
+ * trees we are merging.
+ */
+ if (a && b && c) {
+ if (same(b,c))
+ return c;
+ if (same(a,b))
+ return c;
+ if (same(a,c))
+ return b;
+ }
+ return NULL;
+}
+
+/*
+ * When a CE gets turned into an unmerged entry, we
+ * want it to be up-to-date
+ */
+static void verify_uptodate(struct cache_entry *ce)
+{
+ struct stat st;
+
+ if (!lstat(ce->name, &st)) {
+ unsigned changed = ce_match_stat(ce, &st);
+ if (!changed)
+ return;
+ errno = 0;
+ }
+ if (errno == ENOENT)
+ return;
+ die("Entry '%s' not uptodate. Cannot merge.", ce->name);
+}
+
+/*
+ * If the old tree contained a CE that isn't even in the
+ * result, that's always a problem, regardless of whether
+ * it's up-to-date or not (ie it can be a file that we
+ * have updated but not committed yet).
+ */
+static void reject_merge(struct cache_entry *ce)
+{
+ die("Entry '%s' would be overwritten by merge. Cannot merge.", ce->name);
+}
+
+static int merged_entry_internal(struct cache_entry *merge, struct cache_entry *old, struct cache_entry **dst, int allow_dirty)
+{
+ merge->ce_flags |= htons(CE_UPDATE);
+ if (old) {
+ /*
+ * See if we can re-use the old CE directly?
+ * That way we get the uptodate stat info.
+ *
+ * This also removes the UPDATE flag on
+ * a match.
+ */
+ if (same(old, merge)) {
+ *merge = *old;
+ } else if (!allow_dirty) {
+ verify_uptodate(old);
+ }
+ }
+ merge->ce_flags &= ~htons(CE_STAGEMASK);
+ *dst++ = merge;
+ return 1;
+}
+
+static int merged_entry_allow_dirty(struct cache_entry *merge, struct cache_entry *old, struct cache_entry **dst)
+{
+ return merged_entry_internal(merge, old, dst, 1);
+}
+
+static int merged_entry(struct cache_entry *merge, struct cache_entry *old, struct cache_entry **dst)
+{
+ return merged_entry_internal(merge, old, dst, 0);
+}
+
+static int deleted_entry(struct cache_entry *ce, struct cache_entry *old, struct cache_entry **dst)
+{
+ if (old)
+ verify_uptodate(old);
+ ce->ce_mode = 0;
+ *dst++ = ce;
+ return 1;
+}
+
+static int causes_df_conflict(struct cache_entry *ce, int stage,
+ struct cache_entry **dst_,
+ struct cache_entry **next_,
+ int tail)
+{
+ /* This is called during the merge operation and walking
+ * the active_cache[] array is messy, because it is in the
+ * middle of overlapping copy operation. The invariants
+ * are:
+ * (1) active_cache points at the first (zeroth) entry.
+ * (2) up to dst pointer are resolved entries.
+ * (3) from the next pointer (head-inclusive) to the tail
+ * of the active_cache array have the remaining paths
+ * to be processed. There can be a gap between dst
+ * and next. Note that next is called "src" in the
+ * merge_cache() function, and tail is the original
+ * end of active_cache array when merge_cache() started.
+ * (4) the path corresponding to *ce is not found in (2)
+ * or (3). It is in the gap.
+ *
+ * active_cache -----......+++++++++++++.
+ * ^dst ^next ^tail
+ */
+ int i, next, dst;
+ const char *path = ce->name;
+ int namelen = ce_namelen(ce);
+
+ next = next_ - active_cache;
+ dst = dst_ - active_cache;
+
+ for (i = 0; i < tail; i++) {
+ int entlen, len;
+ const char *one, *two;
+ if (dst <= i && i < next)
+ continue;
+ ce = active_cache[i];
+ if (ce_stage(ce) != stage)
+ continue;
+ /* If ce->name is a prefix of path, then path is a file
+ * that hangs underneath ce->name, which is bad.
+ * If path is a prefix of ce->name, then it is the
+ * other way around which also is bad.
+ */
+ entlen = ce_namelen(ce);
+ if (namelen == entlen)
+ continue;
+ if (namelen < entlen) {
+ len = namelen;
+ one = path;
+ two = ce->name;
+ } else {
+ len = entlen;
+ one = ce->name;
+ two = path;
+ }
+ if (memcmp(one, two, len))
+ continue;
+ if (two[len] == '/')
+ return 1;
+ }
+ return 0;
+}
+
+static int threeway_merge(struct cache_entry *stages[4],
+ struct cache_entry **dst,
+ struct cache_entry **next, int tail)
+{
+ struct cache_entry *old = stages[0];
+ struct cache_entry *a = stages[1], *b = stages[2], *c = stages[3];
+ struct cache_entry *merge;
+ int count;
+
+ /* #5ALT */
+ if (!a && b && c && same(b, c)) {
+ if (old && !same(b, old))
+ return -1;
+ return merged_entry_allow_dirty(b, old, dst);
+ }
+ /* #2ALT and #3ALT */
+ if (!a && (!!b != !!c)) {
+ /*
+ * The reason we need to worry about directory/file
+ * conflicts only in #2ALT and #3ALT case is this:
+ *
+ * (1) For all other cases that read-tree internally
+ * resolves a path, we always have such a path in
+ * *both* stage2 and stage3 when we begin.
+ * Traditionally, the behaviour has been even
+ * stricter and we did not resolve a path without
+ * initially being in all of stage1, 2, and 3.
+ *
+ * (2) When read-tree finishes, all resolved paths (i.e.
+ * the paths that are in stage0) must have come from
+ * either stage2 or stage3. It is not possible to
+ * have a stage0 path as a result of a merge if
+ * neither stage2 nor stage3 had that path.
+ *
+ * (3) It is guaranteed that just after reading the
+ * stages, each stage cannot have directory/file
+ * conflicts on its own, because they are populated
+ * by reading hierarchy of a tree. Combined with
+ * (1) and (2) above, this means that no matter what
+ * combination of paths we take from stage2 and
+ * stage3 as a result of a merge, they cannot cause
+ * a directory/file conflict situation (otherwise
+ * the "guilty" path would have already had such a
+ * conflict in the original stage, either stage2
+ * or stage3). Although its stage2 is synthesized
+ * by overlaying the current index on top of "our
+ * head" tree, --emu23 case also has this guarantee,
+ * by calling add_cache_entry() to create such stage2
+ * entries.
+ *
+ * (4) Only #2ALT and #3ALT lack the guarantee (1).
+ * They resolve paths that exist only in stage2
+ * or stage3. The stage2 tree may have a file DF
+ * while stage3 tree may have a file DF/DF. If
+ * #2ALT and #3ALT rules happen to apply to both
+ * of them, we would end up having DF (coming from
+ * stage2) and DF/DF (from stage3) in the result.
+ * When we attempt to resolve a path that exists
+ * only in stage2, we need to make sure there is
+ * no path that would conflict with it in stage3
+ * and vice versa.
+ */
+ if (c) { /* #2ALT */
+ if (!causes_df_conflict(c, 2, dst, next, tail) &&
+ (!old || same(c, old)))
+ return merged_entry_allow_dirty(c, old, dst);
+ }
+ else { /* #3ALT */
+ if (!causes_df_conflict(b, 3, dst, next, tail) &&
+ (!old || same(b, old)))
+ return merged_entry_allow_dirty(b, old, dst);
+ }
+ /* otherwise we will apply the original rule */
+ }
+ /* #14ALT */
+ if (a && b && c && same(a, b) && !same(a, c)) {
+ if (old && same(old, c))
+ return merged_entry_allow_dirty(c, old, dst);
+ /* otherwise the regular rule applies */
+ }
+ /*
+ * If we have an entry in the index cache ("old"), then we want
+ * to make sure that it matches any entries in stage 2 ("first
+ * branch", aka "b").
+ */
+ if (old) {
+ if (!b || !same(old, b))
+ return -1;
+ }
+ merge = merge_entries(a, b, c);
+ if (merge)
+ return merged_entry(merge, old, dst);
+ if (old)
+ verify_uptodate(old);
+ count = 0;
+ if (a) { *dst++ = a; count++; }
+ if (b) { *dst++ = b; count++; }
+ if (c) { *dst++ = c; count++; }
+ return count;
+}
+
+/*
+ * Two-way merge.
+ *
+ * The rule is to "carry forward" what is in the index without losing
+ * information across a "fast forward", favoring a successful merge
+ * over a merge failure when it makes sense. For details of the
+ * "carry forward" rule, please see <Documentation/git-read-tree.txt>.
+ *
+ */
+static int twoway_merge(struct cache_entry **src, struct cache_entry **dst,
+ struct cache_entry **next, int tail)
+{
+ struct cache_entry *current = src[0];
+ struct cache_entry *oldtree = src[1], *newtree = src[2];
+
+ if (src[3])