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Move <libgen.h> include so we know whether we HAVE_LIBGEN_H -- kevin
[rrdtool.git]
/
doc
/
rpntutorial.pod
diff --git
a/doc/rpntutorial.pod
b/doc/rpntutorial.pod
index
86312cd
..
b830f27
100644
(file)
--- a/
doc/rpntutorial.pod
+++ b/
doc/rpntutorial.pod
@@
-2,8
+2,6
@@
rpntutorial - Reading RRDtool RPN Expressions by Steve Rader
rpntutorial - Reading RRDtool RPN Expressions by Steve Rader
-=for html <div align="right"><a href="rpntutorial.pdf">PDF</a> version.</div>
-
=head1 DESCRIPTION
This tutorial should help you get to grips with RRDtool RPN expressions
=head1 DESCRIPTION
This tutorial should help you get to grips with RRDtool RPN expressions
@@
-26,7
+24,7
@@
RPN expression 2,1,GT evaluates to 1.
Now consider "2,1,LE". This RPN expression could be read as "is
two less than or equal to one?". The natural response is "no"
Now consider "2,1,LE". This RPN expression could be read as "is
two less than or equal to one?". The natural response is "no"
-and thus the RPN expression 2,1,LE evaluates to 0.
+and thus the RPN expression 2,1,LE evaluates to 0.
=head1 Reading the IF Operator
=head1 Reading the IF Operator
@@
-57,7
+55,7
@@
GT, GE and EQ operators.
While compound expressions can look overly complex, they can be
considered elegantly simple. To quickly comprehend RPN expressions,
While compound expressions can look overly complex, they can be
considered elegantly simple. To quickly comprehend RPN expressions,
-you must know the
the
algorithm for evaluating RPN expressions:
+you must know the algorithm for evaluating RPN expressions:
iterate searches from the left to the right looking for an operator.
When it's found, apply that operator by popping the operator and some
number of values (and by definition, not operators) off the stack.
iterate searches from the left to the right looking for an operator.
When it's found, apply that operator by popping the operator and some
number of values (and by definition, not operators) off the stack.
@@
-78,7
+76,7
@@
with multiple logic operators:
1) 20,10,GT,10,20,IF eval is 20,10,GT = 1 result is 1,10,20,IF
read the eval as pop "20 is greater than 10" so push 1
1) 20,10,GT,10,20,IF eval is 20,10,GT = 1 result is 1,10,20,IF
read the eval as pop "20 is greater than 10" so push 1
-
+
2) 1,10,20,IF eval is 1,10,20,IF = 10 result is 10
read pop "if 1 then 10 else 20" so push 10. Only 10 is left so
2) 1,10,20,IF eval is 1,10,20,IF = 10 result is 10
read pop "if 1 then 10 else 20" so push 10. Only 10 is left so
@@
-100,11
+98,11
@@
but replace the value 20 with the variable "input":
Read eval as "if input > 10 then true" and replace "input,10,GT"
with "A":
Read eval as "if input > 10 then true" and replace "input,10,GT"
with "A":
-
+
2) A,10,input,IF eval is A,10,input,IF
read "if A then 10 else input". Now replace A with it's verbose
2) A,10,input,IF eval is A,10,input,IF
read "if A then 10 else input". Now replace A with it's verbose
-description again
g
and--voila!--you have a easily readable description
+description again and--voila!--you have a easily readable description
of the expression:
if input > 10 then 10 else input
of the expression:
if input > 10 then 10 else input
@@
-141,7
+139,7
@@
traditional notation. Explain why they have different answers.
Answer 1:
3*2+1 = 7 and 3*(2+1) = 9. These expressions have
Answer 1:
3*2+1 = 7 and 3*(2+1) = 9. These expressions have
- different answers because the altering of the plus and
+ different answers because the altering of the plus and
times operators alter the order of their evaluation.
times operators alter the order of their evaluation.